If MO is the mass of an oxygen isotope 8O17, Mp and Mn are the masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is

Question

If MO is the mass of an oxygen isotope 8O17, Mp and Mn are the masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is (A) MOc2 (B) (MO - 17 Mn) c2 (C) (MO - 8 Mp) c2 (D) (. 8 Mp + 9 Mn - MO .)c2

Tardigrade Admin · Accepted Answer

The binding energy is given as BE=Δ mc2 , where Δ m= mass defect, and c= speed of light. ⇒ BE=(8 Mp + 9 Mn - MO)c2

Q. If $M_{O}$ is the mass of an oxygen isotope $_{8} O^{17}, M_{p} an d M_{n}$ are the masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is

$M_{O} c^{2}$

$(M_{O} - 17 M_{n}) c^{2}$

$(M_{O} - 8 M_{p}) c^{2}$

$(8 M_{p} + 9 M_{n} - M_{O}) c^{2}$

The binding energy is given as
$BE = Δ m c^{2}$ , where $Δ m =$ mass defect, and $c =$ speed of light.
$\Rightarrow BE = (8 M_{p} + 9 M_{n} - M_{O}) c^{2}$

Q. If MO​ is the mass of an oxygen isotope 8​O17,Mp​andMn​ are the masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is

MO​c2

(MO​−17Mn​)c2

(MO​−8Mp​)c2

(8Mp​+9Mn​−MO​)c2