If log102, log10(2x-1) and log10(2x+3) be three consecutive terms of an AP, then

Question

If log102, log10(2x-1) and log10(2x+3) be three consecutive terms of an AP, then (A)  x = 0  (B)  x = 1  (C)  x = log2 5  (D)  x = log10 2

Tardigrade Admin · Accepted Answer

Correct answer is (c) x = log2 5

Q. If $l o g_{10} 2, l o g_{10} (2^{x} - 1)$ and $l o g_{10} (2^{x} + 3)$ be three consecutive terms of an AP, then