Question

If $KMn{O}_4$ is reduced by oxalic acid in an acidic medium, then oxidation number of $Mn$ changes from

• A. 4 to 2
• B. 6 to 4
• C. 7 to 2
• D. 7 to 4

Answer 1

Answer: (C)

In acidic medium,
$\stackrel{+7}{Mn{O}_4^{-}}+8H^{+}+5e^{-}\to M{n}^{2+}+4H_{2}O$