If kinetic energy of a proton is increased, nine times the wavelength of the de Broglie wave associated with it would become

Question

If kinetic energy of a proton is increased, nine times the wavelength of the de Broglie wave associated with it would become (A) 3 times (B) 9 times (C) (1/3) times (D) (1/9) times.

Tardigrade Admin · Accepted Answer

λ=(h/√2 m E) (λ1/λ2)=√(E2/E1) =√(9 E1/E1)=3 λ2=(1/3) λ1

Q. If kinetic energy of a proton is increased, nine times the wavelength of the de Broglie wave associated with it would become

$3$ times

$9$ times

$\frac{1}{3}$ times

$\frac{1}{9}$ times.

$λ = \frac{h}{2 m E}$
$\frac{λ _{1}}{λ _{2}} = \frac{E _{2}}{E _{1}}$
$= \frac{9 E _{1}}{E _{1}} = 3$
$λ_{2} = \frac{1}{3} λ_{1}$

Q. If kinetic energy of a proton is increased, nine times the wavelength of the de Broglie wave associated with it would become

3 times

9 times

31​ times

91​ times.

λ=2mE​h​ λ2​λ1​​=E1​E2​​​ =E1​9E1​​​=3 λ2​=31​λ1​

$3$ times

$9$ times

$\frac{1}{3}$ times

$\frac{1}{9}$ times.

$λ = \frac{h}{2 m E}$
$\frac{λ _{1}}{λ _{2}} = \frac{E _{2}}{E _{1}}$
$= \frac{9 E _{1}}{E _{1}} = 3$
$λ_{2} = \frac{1}{3} λ_{1}$