If K1 and K2 are the respective equilibrium constants for the two reactions, XeF6(g)+H2O(g) leftharpoons XeOF4(g)+2HF(g) XeO4(g)+XeF6(g) leftharpoons XeOF4(g)+ XeO3F2(g) The equilibrium constant of the reaction, XeO4(g)+2HF(g) leftharpoons XeO3F2(g)+H2O(g)

Question

If K1 and K2 are the respective equilibrium constants for the two reactions, XeF6(g)+H2O(g) leftharpoons XeOF4(g)+2HF(g) XeO4(g)+XeF6(g) leftharpoons XeOF4(g)+ XeO3F2(g) The equilibrium constant of the reaction, XeO4(g)+2HF(g) leftharpoons XeO3F2(g)+H2O(g) (A) K1/(K2)2 (B) K1.K2 (C) K1/K2 (D) K2/K1

Tardigrade Admin · Accepted Answer

XeF6(g)+H2O(g) leftharpoons XeOF4(g)+2HF(g) K1= ([XeOF4][HF]2/[XeF6][H2O]) ...(i) XeO4(g)+XeF6(g) leftharpoons XeOF4(g)+ XeO3F2(g) K2= ([XeOF4][XeO3F2]/[XeO4][XeF6]) ...(ii) For the reaction, XeO4(g)+2HF(g) leftharpoons XeO3F2(g)+H2O(g) K= ([XeO3F2][H2O]/[XeO4][HF]2) ...(iii) ∴ From Eqs. (i), (ii) and (iii) K= (K2/K1)

$K_{1} / (K_{2})^{2}$

$K_{1} . K_{2}$

$K_{1} / K_{2}$

$K_{2} / K_{1}$

Q. If K1​ and K2​ are the respective equilibrium constants for the two reactions, XeF6​(g)+H2​O(g)⇌XeOF4​(g)+2HF(g) XeO4​(g)+XeF6​(g)⇌XeOF4​(g)+XeO3​F2​(g) The equilibrium constant of the reaction, XeO4​(g)+2HF(g)⇌XeO3​F2​(g)+H2​O(g)

K1​/(K2​)2

K1​.K2​

K1​/K2​

K2​/K1​

$K_{1} / (K_{2})^{2}$

$K_{1} . K_{2}$

$K_{1} / K_{2}$

$K_{2} / K_{1}$