If K1 and K2 are the equilibrium constants of the equilibria A and B respectively, what is the relationship between the two constants? (i) SO2(g)+(1/2)O2(g)leftharpoons SO3(g);K1 (ii) 2SO3(g)leftharpoons 2SO2(g)+O2(g);K2

Question

If K1 and K2 are the equilibrium constants of the equilibria A and B respectively, what is the relationship between the two constants? (i) SO2(g)+(1/2)O2(g)leftharpoons SO3(g);K1 (ii) 2SO3(g)leftharpoons 2SO2(g)+O2(g);K2  (A)  K1=K2  (B)  K1=(1/K2)  (C)  K2=K12  (D)  K12=(1/K2)

Tardigrade Admin · Accepted Answer

SO2+(1/2)O2 oversetK1 mathopleftharpoons SO3 K1=([SO3]/[SO2][O2]1/2) ?(i) 2 SO3 oversetK2 mathopleftharpoons 2SO2+O2 K2=([SO2]2[O2]/[SO3]2) (ii) On squaring the equation (1) and multiply equation (1) and equation (2), we get K12=([SO3]/[SO2]2[O2]) K12× K2=([SO3]2/[SO2]2[O2])× ([SO2]2+[O2]/[SO3]2) K12× K2=1 K2=(1/K12) or K12=(1/K2)

Q. If $K_{1}$ and $K_{2}$ are the equilibrium constants of the equilibria A and B respectively, what is the relationship between the two constants? (i) $S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ S O_{3} (g); K_{1}$ (ii) $2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g); K_{2}$

$K_{1} = K_{2}$

$K_{1} = \frac{1}{K _{2}}$

$K_{2} = K_{1}^{2}$

$K_{1}^{2} = \frac{1}{K _{2}}$

Q. If K1​ and K2​ are the equilibrium constants of the equilibria A and B respectively, what is the relationship between the two constants? (i) SO2​(g)+21​O2​(g)⇌SO3​(g);K1​ (ii) 2SO3​(g)⇌2SO2​(g)+O2​(g);K2​

K1​=K2​

K1​=K2​1​

K2​=K12​

K12​=K2​1​

Q. If $K_{1}$ and $K_{2}$ are the equilibrium constants of the equilibria A and B respectively, what is the relationship between the two constants? (i) $S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ S O_{3} (g); K_{1}$ (ii) $2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g); K_{2}$

$K_{1} = K_{2}$

$K_{1} = \frac{1}{K _{2}}$

$K_{2} = K_{1}^{2}$

$K_{1}^{2} = \frac{1}{K _{2}}$