If isotopic distribution of C-12 and C-14 is 98% and 2% respectively, then the number of C-14 atoms in 12 g of carbon is

Question

If isotopic distribution of C-12 and C-14 is 98% and 2% respectively, then the number of C-14 atoms in 12 g of carbon is (A) 1.032×1022 (B) 3.01×1022 (C) 5.88×1023 (D) 6.02×1023

Tardigrade Admin · Accepted Answer

In 12 g of carbon, the amount of C - 14 =12× 2 /100=0.24 g ∴ C-14 atoms in 0.24 g=(0.24×6.02×1023/14) =1.03×1022 atoms

Q. If isotopic distribution of C-12 and C-14 is 98% and 2% respectively, then the number of C-14 atoms in 12 g of carbon is

$1.032 \times 1 0^{22}$

$3.01 \times 1 0^{22}$

$5.88 \times 1 0^{23}$

$6.02 \times 1 0^{23}$

In $12 g$ of carbon, the amount of $C - 14$
$= 12 \times 2/100 = 0.24 g$
$∴ C - 14$ atoms in $0.24 g = \frac{0.24 \times 6.02 \times 1 0 ^{23}}{14}$
$= 1.03 \times 1 0^{22}$ atoms

Q. If isotopic distribution of C-12 and C-14 is 98% and 2% respectively, then the number of C-14 atoms in 12 g of carbon is

1.032×1022

3.01×1022

5.88×1023

6.02×1023

In 12g of carbon, the amount of C−14 =12×2/100=0.24g ∴C−14 atoms in 0.24g=140.24×6.02×1023​ =1.03×1022 atoms

$1.032 \times 1 0^{22}$

$3.01 \times 1 0^{22}$

$5.88 \times 1 0^{23}$

$6.02 \times 1 0^{23}$

In $12 g$ of carbon, the amount of $C - 14$
$= 12 \times 2/100 = 0.24 g$
$∴ C - 14$ atoms in $0.24 g = \frac{0.24 \times 6.02 \times 1 0 ^{23}}{14}$
$= 1.03 \times 1 0^{22}$ atoms