If isobutane and n-butane are present in a gas, then how much oxygen should be required for complete combustion of 5 kg of this gas

Question

If isobutane and n-butane are present in a gas, then how much oxygen should be required for complete combustion of 5 kg of this gas (A) 17.9 kg (B) 9 kg (C) 27 kg (D) 1.8 kg

Tardigrade Admin · Accepted Answer

Isobutane and n-butane [C4H10] have same molecular formula; C4H10 + (13/2) O2 → 4CO2 + 5H2O For 58 g of C4H10 208 g O2 is required then for 5 kg of C4H10, O2 required = (5× 208/58) = 17.9 kg

Q. If isobutane and $n$ -butane are present in a gas, then how much oxygen should be required for complete combustion of $5$ kg of this gas

$17.9 k g$

$9 k g$

$27 k g$

$1.8 k g$

Isobutane and $n$ -butane $[C_{4} H_{10}]$ have same molecular formula;
$C_{4} H_{10} + \frac{13}{2} O_{2} \to 4 C O_{2} + 5 H_{2} O$
For $58 g$ of $C_{4} H_{10} 208 g O_{2}$ is required then for $5$ kg of
$C_{4} H_{10}, O_{2}$ required $= \frac{5 \times 208}{58} = 17.9 k g$

Q. If isobutane and n-butane are present in a gas, then how much oxygen should be required for complete combustion of 5 kg of this gas

17.9kg

9kg

27kg

1.8kg