If heat of dissociation of CHCl 2 COOH is 0.7 kcal / mol then Δ H (in kcal) for the reaction: CHCl 2 COOH + KOH longrightarrow CHCl 2 COOK + H 2 O

Question

If heat of dissociation of CHCl 2 COOH is 0.7 kcal / mol then Δ H (in kcal) for the reaction: CHCl 2 COOH + KOH longrightarrow CHCl 2 COOK + H 2 O (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

The required heat released will be (13.7 - heat required to dissociate CHCl 2 COOH ) =13.0 kcal

Q. If heat of dissociation of $C H C l_{2} COO H$ is $0.7 k c a l / m o l$ then $Δ H$ (in kcal) for the reaction :
$C H C l_{2} COO H + K O H ⟶ C H C l_{2} COO K + H_{2} O$

The required heat released will be $(13.7$ - heat required to dissociate $C H C l_{2} COO H$ ) $= 13.0 k c a l$

Q. If heat of dissociation of CHCl2​COOH is 0.7kcal/mol then ΔH (in kcal) for the reaction : CHCl2​COOH+KOH⟶CHCl2​COOK+H2​O

The required heat released will be (13.7 - heat required to dissociate CHCl2​COOH ) =13.0kcal

Q. If heat of dissociation of $C H C l_{2} COO H$ is $0.7 k c a l / m o l$ then $Δ H$ (in kcal) for the reaction :
$C H C l_{2} COO H + K O H ⟶ C H C l_{2} COO K + H_{2} O$

The required heat released will be $(13.7$ - heat required to dissociate $C H C l_{2} COO H$ ) $= 13.0 k c a l$