Q. If force $F$ , acceleration $a$ , and time $T$ are taken as the fundamental physical quantities, the dimensions of length on this system of units are

86 144 Physical World, Units and Measurements Report Error

A

$F A T^{2}$

48%

B

$F A T$

17%

C

$FT$

10%

D

$A T^{2}$

24%

Solution:

$A T^{2} = L T^{- 2} \times T^{2} = [M^{0} L T^{0}]$