If for the given reaction taking place at 25° C in a cell is, (1/2) textCu ( texts) + (1/2) ( textCl)2 ( textg) arrow (1/2) ( textCu)2 + + ( textCl)- having standard e.m.f. of 1.02 volts . Calculate standard free energy change.

Question

If for the given reaction taking place at 25° C in a cell is, (1/2) textCu ( texts) + (1/2) ( textCl)2 ( textg) arrow (1/2) ( textCu)2 + + ( textCl)- having standard e.m.f. of 1.02 volts . Calculate standard free energy change. (A) -98430 J (B) 98430 J (C) 96500 J (D) -96500 J

Tardigrade Admin · Accepted Answer

The relation between free energy change and standard e.m.f. is given by Δ G=-nFE° Δ G=-1× 96500× 1.02 ; Δ G=-98430 .

Q. If for the given reaction taking place at $2 5^{\circ} C$ in a cell is,

$\frac{1}{2} Cu (s) + \frac{1}{2} (Cl)_{2} (g) \to \frac{1}{2} (Cu)^{2 +} + (Cl)^{-}$

having standard e.m.f. of $1.02 v o lt s$ . Calculate standard free energy change.

$- 98430$ $J$

$98430$ $J$

$96500$ $J$

$- 96500$ $J$

The relation between free energy change and standard e.m.f. is given by $Δ G = - n F E^{\circ}$

$Δ G = - 1 \times 96500 \times 1.02$ ;

$Δ G = - 98430$ .

Q. If for the given reaction taking place at 25∘C in a cell is, 21​Cu(s)+21​(Cl)2​(g)→21​(Cu)2++(Cl)− having standard e.m.f. of 1.02volts . Calculate standard free energy change.

−98430 J

98430 J

96500 J

−96500 J