Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If f(x + y) = f(x) f(y) for all x and y and f(5) = 2, f'(0) = 3, then f'(5) is
Q. If f(x + y) = f(x) f(y) for all x and y and f(5) = 2, f'(0) = 3, then f'(5) is
6379
208
Limits and Derivatives
Report Error
A
5
14%
B
6
46%
C
0
30%
D
none of these
10%
Solution:
f
(
x
+
y
)
=
f
(
x
)
f
(
y
)
⇒
f
(
x
+
5
)
=
f
(
x
)
f
(
5
)
=
2
f
(
x
)
⇒
f
′
(
x
+
5
)
=
2
f
′
(
x
)
⇒
f
′
(
0
+
5
)
=
2
f
′
(
0
)
=
2
(
3
)
=
6
⇒
f
′
(
5
)
=
6