Question

If $f(x)=\sin (\frac{\pi }{3}[x]-x^2)$ then the value of $f\left(\sqrt{\frac{\pi }{3}}\right)$ is

• A. 1
• B. -1
• C. 0
• D. $\frac{-3}{4}$

Answer 1

Answer: (C)

$\left[\sqrt{\pi /3}\right]=1\Rightarrow f\left(x\right)=\sin \left(\frac{\pi }{3}-x^2\right)$