Question

If $f(x)=2x^2+bx+c$ and $f(0)=3$ and $f(2)=1$, then $f(1)$ is equal to

• A. $1$
• B. $2$
• C. $0$
• D. $1/2$

Answer 1

Answer: (C)

$f\left(x\right)=2x^2+bx+c$,
$f\left(0\right)=3$
$\Rightarrow 3=c$
and $f\left(2\right)=1$
$\Rightarrow 1=8+2b+c$
$\Rightarrow 2b+3=-7$
$\Rightarrow b=-5$
$\therefore f\left(1\right)=2\times 1^2+\left(-5\right)\times 1+3=2-5+3$
$=0$.