Q.
If f:R→R is a function defined as f(x)=x2+5x+93x2+4x+5, then f is
87
129
Relations and Functions - Part 2
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Solution:
f(x)=x2+5x+93x2+4x+5 D<0,a>0⇒f(x) is always positive D<0,a>0⇒Rf=Rf is into Also, x2+5x+93x2+4x+5=95 22x2+11x=0 11x(2x+1)=0 x=0,2−1 ⇒f(0)=f(2−1)=95⇒ f is many one