If enthalpy of atomisation for mathrmBr2(t) is × mathrmkJ / mathrmmol and bond enthalpy for Br2 is y k J / m o l , the relation between them

Question

If enthalpy of atomisation for mathrmBr2(t) is × mathrmkJ / mathrmmol and bond enthalpy for Br2 is y k J / m o l , the relation between them (A) is x < y (B) is x>y (C) does not exist (D) is x=7y

Tardigrade Admin · Accepted Answer

Based on hess law it can be given as <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-gzniu17nowoj.png" /> As Δ Ha t o m i s a t i o n=Δ HV a p .+ Bond Energy Hence x>y

Q. If enthalpy of atomisation for $Br_{2} (t)$ is $\times kJ / mol$ and bond enthalpy for $B r_{2}$ is y $k J / m o l$ , the relation between them

is $x < y$

is $x > y$

does not exist

is $x = 7 y$

Based on hess law it can be given as

As $Δ H_{a t o mi s a t i o n} = Δ H_{Va p .} +$ Bond Energy

Hence $x > y$

Q. If enthalpy of atomisation for Br2​(t) is ×kJ/mol and bond enthalpy for Br2​ is y kJ/mol , the relation between them

is x<y

is x>y