If EA, EB and EC represent kinetic energies of an electron, alpha particle and proton respectively and each moving with same de-Broglie wavelength, then choose the correct increasing representation,

Question

If EA, EB and EC represent kinetic energies of an electron, alpha particle and proton respectively and each moving with same de-Broglie wavelength, then choose the correct increasing representation, (A) EA=EB=EC (B) EA > EB > EC (C) EB > EC > EA (D) EA < EC < EB

Tardigrade Admin · Accepted Answer

As we know that, λ=(h/m v)=(h/√2 m KE ) ∵ λ propto (1/√m) Mass of e, α and p are me < mp < mα. The correct order is EA < EC < EB.

Q. If $E_{A}, E_{B}$ and $E_{C}$ represent kinetic energies of an electron, alpha particle and proton respectively and each moving with same de-Broglie wavelength, then choose the correct increasing representation,

$E_{A} = E_{B} = E_{C}$

$E_{A} > E_{B} > E_{C}$

$E_{B} > E_{C} > E_{A}$

$E_{A} < E_{C} < E_{B}$

As we know that,
$λ = \frac{h}{m v} = \frac{h}{2 m K E}$
$∵ λ \propto \frac{1}{m}$
Mass of $e, α$ and $p$ are $m_{e} < m_{p} < m_{α}$ .
The correct order is $E_{A} < E_{C} < E_{B}$ .

Q. If EA​,EB​ and EC​ represent kinetic energies of an electron, alpha particle and proton respectively and each moving with same de-Broglie wavelength, then choose the correct increasing representation,

EA​=EB​=EC​

EA​>EB​>EC​

EB​>EC​>EA​

EA​<EC​<EB​