Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
If Δ H is the change in enthalpy and Δ E the change in internal energy for a gaseous reaction then
Q. If
Δ
H
is the change in enthalpy and
Δ
E
the change in internal energy for a gaseous reaction then
296
172
NTA Abhyas
NTA Abhyas 2022
Report Error
A
Δ
H
is always greater than
Δ
E
B
Δ
H
<
Δ
E
only if the number of moles of the products is greater than the number of the reactants
C
Δ
H
is always less than
Δ
E
D
Δ
H
<
Δ
E
only if the number of moles of the products is less than the number of moles of the reactants
Solution:
The change in enthalpy and the change in internal energy for a gaseous reaction is given by
Δ
H
=
Δ
E
+
Δ
n
g
RT
If
Δ
n
=
−
v
e
than
Δ
H
<
Δ
E
.