Question

If $\frac{dy}{dx}+\frac{y}{x}=x^2$, then $2y(2)-y(1)=$

• A. $\frac{11}{4}$
• B. $\frac{9}{4}$
• C. $\frac{15}{4}$
• D. $\frac{13}{4}$

Answer 1

Answer: (C)

$y\cdot x=\frac{x^4}{4}+C$
$2y(2)-y(1)=\frac{15}{4}$