Question

If $Co{s}^{-1}p+Co{s}^{-1}q+Co{s}^{-1}r=\pi$ then $p^2+q^2+r^2+2pqr=$

• A. 3
• B. 1
• C. 2
• D. $-1$

Answer 1

Answer: (B)

Correct answer is (b) 1