If C the concentration of a weak electrolyte, α is the degree of ionization and Ka is the acid ionization constant, then the correct relationship between α ,C and Ka is

Question

If C the concentration of a weak electrolyte, α is the degree of ionization and Ka is the acid ionization constant, then the correct relationship between α ,C and Ka is (A) α 2=√(Ka/C) (B) α 2=√(C/Ka) (C) α =√(C/Ka) (D) α =√(Ka/C)

Tardigrade Admin · Accepted Answer

According to the Ostwaldâs dilution formula (α )2=(K (. 1 - α .)/C) . But for weak electrolytes &#945; is very small. So that (.1-α .) can be neglected. So that α =√(Ka/C) .

Q. If $C$ the concentration of a weak electrolyte, $α$ is the degree of ionization and $K_{a}$ is the acid ionization constant, then the correct relationship between $α, C$ and $K_{a}$ is

$α^{2} = \frac{K _{a}}{C}$

$α^{2} = \frac{C}{K _{a}}$

$α = \frac{C}{K _{a}}$

$α = \frac{K _{a}}{C}$

According to the Ostwald’s dilution formula $(α)^{2} = \frac{K ( 1 - α )}{C}$ . But for weak electrolytes α is very small. So that $(1 - α)$ can be neglected. So that $α = \frac{K _{a}}{C}$ .

Q. If C the concentration of a weak electrolyte, α is the degree of ionization and Ka​ is the acid ionization constant, then the correct relationship between α,C and Ka​ is

α2=CKa​​​

α2=Ka​C​​

α=Ka​C​​

α=CKa​​​