We know that a vector perpendicular to a and in the plane containing b and c is given by a×(b×c).
Given a=2i^+3j^−k^ b=i^+2j^−5k^ and c=3i^+5j^−k^ ∴b×c=∣∣i^13j^25k^−5−1∣∣=23i^−14j^−k^
Now, a×(b×c)=∣∣i^223j^3−14k^−1−1∣∣ =(−3−14)i^−j^(−2+23)+k^(−28−69) =−17i^−21j^−97k^
Which is the required vector.