Q.
If α=x1+x3+…x199 and β=x2+x4+…x200 , such that x1,x2,x3,...............x200 are in arithmetic progression, then their common difference is
1535
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NTA AbhyasNTA Abhyas 2020Sequences and Series
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Solution:
In the A.P.x1,x2,x3,……….x200 let the common difference be d . ∴α=x1+x3+……….+x199=2100(x1+x199)=50(2x1+198d) β=x2+x4+………x200=2100(x2+x200)
= 50(x1+d+x1+199d) =50(2x1+200d) β−α=100d d=100β−α