If a thermometer reads freezing point of water as 20° C and boiling point as 150° C , how much will the thermometer read when the actual temperature is 60° C ?

Question

If a thermometer reads freezing point of water as 20° C and boiling point as 150° C , how much will the thermometer read when the actual temperature is 60° C ? (A) 98° C (B) 110° C (C) 40° C (D) 60° C

Tardigrade Admin · Accepted Answer

The temperature on any scale can be converted into another scale by (x - L F P/U F P - L F P)= constant for all scales (x - 20/150 - 20)=(60/100)⇒ x=98° C .

Q. If a thermometer reads freezing point of water as $2 0^{\circ} C$ and boiling point as $15 0^{\circ} C$ , how much will the thermometer read when the actual temperature is $6 0^{\circ} C$ ?

$9 8^{\circ} C$

$11 0^{\circ} C$

$4 0^{\circ} C$

$6 0^{\circ} C$

The temperature on any scale can be converted into another scale by
$\frac{x - L FP}{U FP - L FP} =$ constant for all scales
$\frac{x - 20}{150 - 20} = \frac{60}{100} \Rightarrow x = 9 8^{\circ} C$ .

Q. If a thermometer reads freezing point of water as 20∘C and boiling point as 150∘C , how much will the thermometer read when the actual temperature is 60∘C ?

98∘C

110∘C

40∘C

60∘C