If a proton enters perpendicularly a magnetic field with velocity v, then time period of revolution is T. If proton enters with velocity 2 v, then time period will be

Question

If a proton enters perpendicularly a magnetic field with velocity v, then time period of revolution is T. If proton enters with velocity 2 v, then time period will be (A) T (B) 2 T (C) 3 T (D) 4 T

Tardigrade Admin · Accepted Answer

T=(2 π m/q B) ⇒ independent of v

Q. If a proton enters perpendicularly a magnetic field with velocity $v$ , then time period of revolution is $T$ . If proton enters with velocity $2 v$ , then time period will be

T

2 T

3 T

4 T

$T = \frac{2 πm}{qB} \Rightarrow$ independent of $v$

Q. If a proton enters perpendicularly a magnetic field with velocity v, then time period of revolution is T. If proton enters with velocity 2v, then time period will be

T

2 T

3 T

4 T

T=qB2πm​⇒ independent of v

Q. If a proton enters perpendicularly a magnetic field with velocity $v$ , then time period of revolution is $T$ . If proton enters with velocity $2 v$ , then time period will be

$T = \frac{2 πm}{qB} \Rightarrow$ independent of $v$