If a proton and anti-proton come close to each other and annihilate, how much energy will be released?

Question

If a proton and anti-proton come close to each other and annihilate, how much energy will be released? (A) 1.5× 10- 10 J (B) 3× 10- 10 J (C) 4.5× 10- 10 J (D) 2× 10- 10 J

Tardigrade Admin · Accepted Answer

Mass of proton = mass of anti-proton =1.67× 10- 27kg=1 amu Energy equivalent to amu = 931MeV . So, energy equivalent to 2amu =2× 931 MeV =1862× 106× 1.6× 10- 19 =2.97× 10- 10J ≈3× 10- 10J

Q. If a proton and anti-proton come close to each other and annihilate, how much energy will be released?

$1.5 \times 1 0^{- 10} J$

$3 \times 1 0^{- 10} J$

$4.5 \times 1 0^{- 10} J$

$2 \times 1 0^{- 10} J$

Mass of proton = mass of anti-proton
$= 1.67 \times 1 0^{- 27} k g = 1 am u$
Energy equivalent to amu = $931 M e V$ .
So, energy equivalent to $2 am u$ $= 2 \times 931$ $M e V$
$= 1862 \times 1 0^{6} \times 1.6 \times 1 0^{- 19}$
$= 2.97 \times 1 0^{- 10} J$
$\approx 3 \times 1 0^{- 10} J$

Q. If a proton and anti-proton come close to each other and annihilate, how much energy will be released?

1.5×10−10J

3×10−10J

4.5×10−10J

2×10−10J

Mass of proton = mass of anti-proton =1.67×10−27kg=1amu Energy equivalent to amu = 931MeV . So, energy equivalent to 2amu =2×931 MeV =1862×106×1.6×10−19 =2.97×10−10J ≈3×10−10J

$1.5 \times 1 0^{- 10} J$

$3 \times 1 0^{- 10} J$

$4.5 \times 1 0^{- 10} J$

$2 \times 1 0^{- 10} J$

Mass of proton = mass of anti-proton
$= 1.67 \times 1 0^{- 27} k g = 1 am u$
Energy equivalent to amu = $931 M e V$ .
So, energy equivalent to $2 am u$ $= 2 \times 931$ $M e V$
$= 1862 \times 1 0^{6} \times 1.6 \times 1 0^{- 19}$
$= 2.97 \times 1 0^{- 10} J$
$\approx 3 \times 1 0^{- 10} J$