If a mixture of isobutane and n-butane are present in a gas, then calculate the mass of oxygen required for complete combustion of 5 kg of this gas

Question

If a mixture of isobutane and n-butane are present in a gas, then calculate the mass of oxygen required for complete combustion of 5 kg of this gas (A) 1.8 kg (B) 9 kg (C) 17.9 kg (D) 27 kg

Tardigrade Admin · Accepted Answer

Isobutane and n-butane [C4 H10] have same molecular formula; C4H10+(13/2)O2 arrow 4CO2+5H2O For 58 gm of C4H10 208gm O2 is required then for 5kg of C4H10 O2=(5 × 208/58)=17.9 kg

Q. If a mixture of isobutane and n-butane are present in a gas, then calculate the mass of oxygen required for complete combustion of $5$ $k g$ of this gas

$1.8$ $k g$

$9$ $k g$

$17.9$ $k g$

$27$ $k g$

Isobutane and n-butane $[C_{4} H_{10}]$ have same molecular formula; $C_{4} H_{10} + \frac{13}{2} O_{2} \to 4 C O_{2} + 5 H_{2} O$

For $58$ $g m$ of $C_{4} H_{10}$ $208 g m$ $O_{2}$ is required then for $5 k g$ of $C_{4} H_{10}$ $O_{2} = \frac{5 \times 208}{58} = 17.9 k g$

Q. If a mixture of isobutane and n-butane are present in a gas, then calculate the mass of oxygen required for complete combustion of 5 kg of this gas

1.8 kg

9 kg

17.9 kg

27 kg