Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If A.M. of x1, x2, ...., xn is barx, then A.M. of ax1 + b, ax2 + b, ax3 + b, ..., axn + b is
Q. If
A
.
M
.
of
x
1
,
x
2
,
....
,
x
n
is
x
ˉ
, then
A
.
M
.
of
a
x
1
+
b
,
a
x
2
+
b
,
a
x
3
+
b
,
...
,
a
x
n
+
b
is
1818
258
Statistics
Report Error
A
a
x
ˉ
19%
B
a
x
ˉ
+
b
33%
C
a
x
ˉ
+
nb
38%
D
None of these
10%
Solution:
A
.
M
.
=
n
(
a
x
1
+
b
)
+
(
a
x
2
+
b
)
+
....
+
(
a
x
n
+
b
)
=
n
a
(
x
1
+
x
2
+
....
+
x
n
)
+
nb
=
n
a
(
x
1
+
x
2
+
....
+
x
n
)
+
b
=
a
x
ˉ
+
b