If a = log x yz , b = log y zx c = log z xy where x , y , z are positive reals not equal to unity, then a b c-a-b-c is equal to :

Question

If a = log x yz , b = log y zx c = log z xy where x , y , z are positive reals not equal to unity, then a b c-a-b-c is equal to : (A) 2 (B) 1 (C) -1 (D) zero

Tardigrade Admin · Accepted Answer

consider -[ a + b + c - abc ] abc = a + b + c +2

Q. If $a = lo g_{x} yz, b = lo g_{y} z x & c = lo g_{z} x y$ where $x, y, z$ are positive reals not equal to unity, then $ab c - a - b - c$ is equal to :

2

1

-1

zero

consider $- [a + b + c - ab c] ab c = a + b + c + 2$

Q. If a=logx​yz,b=logy​zx&c=logz​xy where x,y,z are positive reals not equal to unity, then abc−a−b−c is equal to :

2

1

-1

zero

consider −[a+b+c−abc]abc=a+b+c+2

Q. If $a = lo g_{x} yz, b = lo g_{y} z x & c = lo g_{z} x y$ where $x, y, z$ are positive reals not equal to unity, then $ab c - a - b - c$ is equal to :

consider $- [a + b + c - ab c] ab c = a + b + c + 2$