Question

If $a,b,c,d,e,f$ are in arithmetic progression. Then $e-c$ is equal to

• A. $2\left(c-a\right)$
• B. $2\left(d-c\right)$
• C. $2\left(f-d\right)$
• D. $d-c$

Answer 1

Answer: (B)

$a,b,c,d,e$ are in A.P.
Let common difference $=D$
$\therefore e-c=\left(a+4D\right)-\left(a+2D\right)=2D=2(d-c)$