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Tardigrade
Question
Mathematics
If a+b+c=1, a2+b2+c2=9 and a3+b3+c3=1, then the value of (1/a)+(1/b)+(1/c) is :
Q. If
a
+
b
+
c
=
1
,
a
2
+
b
2
+
c
2
=
9
and
a
3
+
b
3
+
c
3
=
1
, then the value of
a
1
+
b
1
+
c
1
is :
424
95
Sequences and Series
Report Error
A
3
2
B
5
C
6
D
1
Solution:
Correct answer is (d) 1