If a and b are fixed non-zero constants, then the derivative of (a/x4)-(b/x2)+ operatornameCos x is ma+nb-p where

Question

If a and b are fixed non-zero constants, then the derivative of (a/x4)-(b/x2)+ operatornameCos x is ma+nb-p where (A) m=4 x3 ; n=(-2/x3) ; p= sin x (B) m=(-4/x5) ; n=(2/x3) ; p= sin x (C) m=(-4/x5) ; n=(-2/x3) ; p=- sin x (D) m=4 x3 ; n=(2/x3) ; p=- sin x

Tardigrade Admin · Accepted Answer

( d / dx )(( a / x 4)-( b / x 2)+ cos x )=(-(4 a / x 5)+(2 b / x 3)- sin x ) = ma + nb - p m =-(4/ x 5) ; n =(+2/ x 3) ; p = sin x

Q. If $a$ and $b$ are fixed non-zero constants, then the derivative of $\frac{a}{x ^{4}} - \frac{b}{x ^{2}} + Cos x$ is $ma + nb - p$ where

$m = 4 x^{3}; n = \frac{- 2}{x ^{3}}; p = sin x$

$m = \frac{- 4}{x ^{5}}; n = \frac{2}{x ^{3}}; p = sin x$

$m = \frac{- 4}{x ^{5}}; n = \frac{- 2}{x ^{3}}; p = - sin x$

$m = 4 x^{3}; n = \frac{2}{x ^{3}}; p = - sin x$

$\frac{d}{d x} (\frac{a}{x ^{4}} - \frac{b}{x ^{2}} + cos x) = (- \frac{4 a}{x ^{5}} + \frac{2 b}{x ^{3}} - sin x)$
$= ma + nb - p$
$m = - \frac{4}{x ^{5}}; n = \frac{+ 2}{x ^{3}}; p = sin x$

Q. If a and b are fixed non-zero constants, then the derivative of x4a​−x2b​+Cosx is ma+nb−p where

m=4x3;n=x3−2​;p=sinx

m=x5−4​;n=x32​;p=sinx

m=x5−4​;n=x3−2​;p=−sinx

m=4x3;n=x32​;p=−sinx