Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If A = [3&7 1&2], then the value of the determinant |A2013 - 3A2012| is equal to
Q. If
A
=
[
3
1
7
2
]
, then the value of the determinant
∣
A
2013
−
3
A
2012
∣
is equal to
3004
212
Determinants
Report Error
A
8
16%
B
-8
24%
C
9
28%
D
-7
32%
Solution:
∣
A
2013
−
3
A
2012
∣
=
∣
A
2012
∣∣
A
−
3
I
∣
=
∣
A
∣
2012
∣
A
−
3
I
∣
=
(
1
)
∣
∣
0
1
7
−
1
∣
∣
=
(
1
)
(
−
7
)
=
−
7.