If A=[1 2 3 4 5 6 7 8 9], then (A A')'=

Question

If A=[1 2 3 4 5 6 7 8 9], then (A A')'= (A) [14 32 50 32 122 194 50 194 256] (B) [14 50 32 32 122 194 50 194 122] (C) [14 32 50 32 194 122 32 122 77] (D) [ beginarrayccc14 32 50 32 77 122 50 122 194 endarray]

Tardigrade Admin · Accepted Answer

We have, A=[1 2 3 4 5 6 7 8 9] ⇒ A'=[1 4 7 2 5 8 3 6 9] Now, A ⋅ A'=[1 2 3 4 5 6 7 8 9] [1 4 7 2 5 8 3 6 9] =[1+4+9 4+10+18 7+16+27 4+10+18 16+25+36 28+40+54 7+16+27 28+40+54 49+64+81] So, A A'=[14 32 50 32 77 122 50 122 194](A A')'=[14 32 50 32 77 122 50 122 194]

Q. If $A = ⎣ ⎡ 147258369 ⎦ ⎤$ , then $(A A^{'})^{'} =$

$⎣ ⎡ 1432503212219450194256 ⎦ ⎤$

$⎣ ⎡ 1432505012219432194122 ⎦ ⎤$

$⎣ ⎡ 143232321941225012277 ⎦ ⎤$

$⎣ ⎡ 143250327712250122194 ⎦ ⎤$

Q. If A=⎣⎡​147​258​369​⎦⎤​, then (AA′)′=

⎣⎡​143250​32122194​50194256​⎦⎤​

⎣⎡​143250​50122194​32194122​⎦⎤​

⎣⎡​143232​32194122​5012277​⎦⎤​

⎣⎡​143250​3277122​50122194​⎦⎤​

Q. If $A = ⎣ ⎡ 147258369 ⎦ ⎤$ , then $(A A^{'})^{'} =$

$⎣ ⎡ 1432503212219450194256 ⎦ ⎤$

$⎣ ⎡ 1432505012219432194122 ⎦ ⎤$

$⎣ ⎡ 143232321941225012277 ⎦ ⎤$

$⎣ ⎡ 143250327712250122194 ⎦ ⎤$