If A-1=(1/11) beginpmatrix-3 4 5 -3 endpmatrix, then A =

Question

If A-1=(1/11) beginpmatrix-3 4 5 -3 endpmatrix, then A = (A) -(1/11) beginpmatrix3 4 5 3 endpmatrix (B) (1/11) beginpmatrix3 4 5 3 endpmatrix (C)  beginpmatrix-3 4 -5 3 endpmatrix (D)  beginpmatrix3 4 5 3 endpmatrix

Tardigrade Admin · Accepted Answer

A=[3 4 5 3] ⇒ A-1=(1/9-20)[3 -4 -5 3] =(1/-11)[3 -4 -5 3] =(1/11)[-3 4 5 -3]

Q. If $A^{- 1} = \frac{1}{11} (- 3 5 4 - 3)$ , then $A =$

$- \frac{1}{11} (3543)$

$\frac{1}{11} (3543)$

$(- 3 - 5 43)$

$(3543)$

$(- 3 5 4 - 3)$

$A = [3543]$
$\Rightarrow A^{- 1} = \frac{1}{9 - 20} [3 - 5 - 4 3]$
$= \frac{1}{- 11} [3 - 5 - 4 3]$
$= \frac{1}{11} [- 3 5 4 - 3]$

Q. If A−1=111​(−35​4−3​), then A=

−111​(35​43​)

111​(35​43​)

(−3−5​43​)

(35​43​)

(−35​4−3​)

A=[35​43​] ⇒A−1=9−201​[3−5​−43​] =−111​[3−5​−43​] =111​[−35​4−3​]