If 4x + 3

Question

If 4x + 3 < 6x + 7, then x∈ (A) (2, ∞) (B) (-2, ∞) (C) ( -∞, 2) (D) (-∞, ∞)

Tardigrade Admin · Accepted Answer

We have, 4x + 3 < 6x + 7. or 4x - 6x < 7 - 3 or -2x < 4 or x > - 2 i.e., all real numbers which are greater than -2, are solutions of the given inequality. Hence, the solution set is (-2, ∞).

Q. If $4 x + 3 < 6 x + 7$ , then $x \in$

( $2$ , $\infty$ )

( $- 2$ , $\infty$ )

( $- \infty$ , $2$ )

( $- \infty$ , $\infty$ )

We have, $4 x + 3 < 6 x + 7$ .
or $4 x - 6 x < 7 - 3$ or $- 2 x < 4$ or $x > - 2$
i.e., all real numbers which are greater than $- 2$ , are solutions of the given inequality. Hence, the solution set is ( $- 2$ , $\infty$ ).

Q. If 4x+3<6x+7, then x∈

(2, ∞)

(−2, ∞)

( −∞, 2)

(−∞, ∞)