If [3&-1 0&6][3x 1]+[-2x 3]=[8 9] the value of x is

Question

If [3&-1 0&6][3x 1]+[-2x 3]=[8 9] the value of x is (A) 7 (B) -(2/9) (C) -(3/8) (D) None of the options

Tardigrade Admin · Accepted Answer

Given, [3&-1 0&6][3x 1] +[-2x 3]= [8 9] LH S =[3 -1 0 6][3 x 1]+[-2 x 3] =[9 x+(-1) 0+6]+[-2 x 3] =[9 x-1 6]+[-2 x 3] =[9 x-1-2 x 6+3]=[7 x-1 9] Now, [7 x-1 9]=[8 9] ∴ 7 ×-1=8 ⇒ 7 x=9 ⇒ x=(9/7)

Q. If $[30 - 1 6] [3 x 1] + [- 2 x 3] = [89]$ the value of $x$ is

$7$

$- \frac{2}{9}$

$- \frac{3}{8}$

None of the options

Given, $[30 - 1 6] [3 x 1] + [- 2 x 3] = [89]$
$L H S = [30 - 1 6] [3 x 1] + [- 2 x 3]$
$= [9 x + (- 1) 0 + 6] + [- 2 x 3]$
$= [9 x - 1 6] + [- 2 x 3] = [9 x - 1 - 2 x 6 + 3] = [7 x - 1 9]$
Now, $[7 x - 1 9] = [89]$
$∴ 7 \times - 1 = 8$
$\Rightarrow 7 x = 9$
$\Rightarrow x = \frac{9}{7}$

Q. If [30​−16​][3x1​]+[−2x3​]=[89​] the value of x is

7

−92​

−83​

None of the options

Given, [30​−16​][3x1​]+[−2x3​]=[89​] LHS=[30​−16​][3x1​]+[−2x3​] =[9x+(−1)0+6​]+[−2x3​] =[9x−16​]+[−2x3​]=[9x−1−2x6+3​]=[7x−19​] Now, [7x−19​]=[89​] ∴7×−1=8 ⇒7x=9 ⇒x=79​

Q. If $[30 - 1 6] [3 x 1] + [- 2 x 3] = [89]$ the value of $x$ is

$7$

$- \frac{2}{9}$

$- \frac{3}{8}$

Given, $[30 - 1 6] [3 x 1] + [- 2 x 3] = [89]$
$L H S = [30 - 1 6] [3 x 1] + [- 2 x 3]$
$= [9 x + (- 1) 0 + 6] + [- 2 x 3]$
$= [9 x - 1 6] + [- 2 x 3] = [9 x - 1 - 2 x 6 + 3] = [7 x - 1 9]$
Now, $[7 x - 1 9] = [89]$
$∴ 7 \times - 1 = 8$
$\Rightarrow 7 x = 9$
$\Rightarrow x = \frac{9}{7}$