Question

If $2f\left(x+1\right)+f\left(\frac{1}{x+1}\right)=2x$,then $f\left(2\right)$ is equal to

Answer 1

Answer: 1.67

$2f\left(x+1\right)+f\left(\frac{1}{x+1}\right)=2x....\left(i\right)$
at $x=1$
$2f\left(2\right)+f\left(\frac{1}{2}\right)=\mathrm{2.....}\left(ii\right)$
from equation (i)
Putting $x=-1/2$
$\Rightarrow 2f\left(\frac{1}{2}\right)+f\left(2\right)=-\mathrm{1....}\left(iii\right)$
from equation (ii) and equation (iii)
$f\left(2\right)=5/3=1.67$