If 2A+3B =[ 2&-1 &4 3&2& 5 ] and A+2B [ 5&0 &3 1&6& 2 ] then B =

Question

If 2A+3B =[ 2&-1 &4 3&2& 5 ] and A+2B [ 5&0 &3 1&6& 2 ] then B = (A) [ 8&1 &2 1&10& 1 ]  (B) [ 8&1 &-2 -1&10& -1 ]  (C) [ 8&1 &2 -1&10& -1 ]  (D) [ 8&-1 &2 -1&10& -1 ]

Tardigrade Admin · Accepted Answer

We have 2A + 3B = [2&-1&4 3&2&5] dots(i) and A + 2B = [5&0&3 1&6&2] dots(ii) Multiply Eq. (ii) by 2 and subtracting Eq.(i) from (ii), we get B = 2 [5&0&3 1&6&2] -[2&-1&4 3&2&5] = [8&1&2 -1&10&-1]

Q. If $2 A + 3 B = [23 - 1 2 45]$ and $A + 2 B [510632]$ then $B =$

$[8111021]$

$[8 - 1 110 - 2 - 1]$

$[8 - 1 110 2 - 1]$

$[8 - 1 - 1 10 2 - 1]$

We have
$2 A + 3 B = [23 - 1 2 45] \dots (i)$
and $A + 2 B = [510632] \dots (ii)$
Multiply Eq. (ii) by 2 and subtracting Eq.(i) from (ii), we get
$B = 2 [510632] - [23 - 1 2 45]$
$= [8 - 1 110 2 - 1]$

Q. If 2A+3B=[23​−12​45​] and A+2B[51​06​32​]then B=

[81​110​21​]

[8−1​110​−2−1​]

[8−1​110​2−1​]

[8−1​−110​2−1​]