If 200 MeV energy is released in the fission of a single nucleus of 92 U 235, how many fissions must occur per second to produce a power of 1 kW ?

Question

If 200 MeV energy is released in the fission of a single nucleus of 92 U 235, how many fissions must occur per second to produce a power of 1 kW ? (A) 3.125 × 1013 (B) 1.52 × 106 (C) 3.125 × 1012 (D) 3.125 × 1014

Tardigrade Admin · Accepted Answer

Total energy / s =1000 J Energy released/fission =200 MeV =200 × 1.6 × 10-13 J =3.2 × 10-11 J ∴ Number of fission / s =(1000/3.2 × 10-11) =3.12 × 1013

Q. If $200 M e V$ energy is released in the fission of a single nucleus of $_{92} U^{235}$ , how many fissions must occur per second to produce a power of $1 kW ?$

$3.125 \times 1 0^{13}$

$1.52 \times 1 0^{6}$

$3.125 \times 1 0^{12}$

$3.125 \times 1 0^{14}$

Total energy $/ s = 1000 J$
Energy released/fission $= 200 M e V$
$= 200 \times 1.6 \times 1 0^{- 13} J$
$= 3.2 \times 1 0^{- 11} J$
$∴$ Number of fission $/ s = \frac{1000}{3.2 \times 1 0 ^{- 11}}$
$= 3.12 \times 1 0^{13}$

Q. If 200MeV energy is released in the fission of a single nucleus of 92​U235, how many fissions must occur per second to produce a power of 1kW?

3.125×1013

1.52×106

3.125×1012

3.125×1014