If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n=2 is :

Question

If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n=2 is : (A) 10.2 eV (B) 0 eV (C) 3.4 eV (D) 6.8 eV

Tardigrade Admin · Accepted Answer

Energy required to remove an electron from n th orbit is, En =- (13.6/n2) Here, n =2 Therefore, E2= -(13.6/22)= -3.4 V

Q. If $13.6 e V$ energy is required to ionize the hydrogen atom, then the energy required to remove an electron from $n = 2$ is :

$10.2 e V$

$0 e V$

$3.4 e V$

$6.8 e V$

Energy required to remove an electron from $n$ th orbit is,
$E_{n} = - \frac{13.6}{n ^{2}}$
Here, $n = 2$
Therefore, $E_{2} = - \frac{13.6}{2 ^{2}} = - 3.4 V$

Q. If 13.6eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n=2 is :

10.2eV

0eV

3.4eV

6.8eV