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Question
Mathematics
If [ 1&2 &-1 1&x-2& -1 x&1&1 ] is singular, then the value of x is
Q. If
⎣
⎡
1
1
x
2
x
−
2
1
−
1
−
1
1
⎦
⎤
is singular, then the value of
x
is
4140
156
KCET
KCET 2011
Determinants
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A
2
25%
B
3
26%
C
1
34%
D
0
16%
Solution:
Let
A
=
⎣
⎡
1
1
x
2
x
−
2
1
−
1
1
1
⎦
⎤
if the matrix
A
is singular, then
∣
A
∣
=
0
⎣
⎡
1
1
x
2
x
−
2
1
−
1
1
1
⎦
⎤
=
0
Expand with respect to
R
1
⇒
1
(
x
−
2
−
1
)
−
2
(
1
−
x
)
−
1
(
1
−
x
2
+
2
x
)
=
0
⇒
x
−
3
−
2
+
2
x
−
1
+
x
2
−
2
x
=
0
⇒
x
2
+
x
−
6
=
0
⇒
(
x
−
2
)
(
x
+
3
)
=
0
⇒
x
=
2
,
−
3