If |0&3&2b 2&0&1 4&-1&6| is singular, then the value of b is equal to

Question

If |0&3&2b 2&0&1 4&-1&6| is singular, then the value of b is equal to (A) - 3 (B) 3 (C) - 6 (D) 6

Tardigrade Admin · Accepted Answer

A matrix whose determinant value is zero, is known as singular matrix. Hence, |0 3 2 b 2 0 1 4 -1 6|=0 Expanding along R1, we get 0(0+1)-3(12-4)+2 b(-2-0)=0 ⇒ -24-4 b=0 ∴ b=-6

Q. If $∣ ∣ 024 30 - 1 2 b 16 ∣ ∣$ is singular, then the value of $b$ is equal to

- 3

3

- 6

6

- 2

A matrix whose determinant value is zero, is known as singular matrix.
Hence, $∣ ∣ 024 30 - 1 2 b 16 ∣ ∣ = 0$
Expanding along
$R_{1}$ , we get $0 (0 + 1) - 3 (12 - 4) + 2 b (- 2 - 0) = 0$
$\Rightarrow - 24 - 4 b = 0$
$∴$ $b = - 6$

Q. If ∣∣​024​30−1​2b16​∣∣​ is singular, then the value of b is equal to

- 3

3

- 6

6

- 2

A matrix whose determinant value is zero, is known as singular matrix. Hence, ∣∣​024​30−1​2b16​∣∣​=0 Expanding along R1​, we get 0(0+1)−3(12−4)+2b(−2−0)=0 ⇒−24−4b=0 ∴ b=−6

Q. If $∣ ∣ 024 30 - 1 2 b 16 ∣ ∣$ is singular, then the value of $b$ is equal to

A matrix whose determinant value is zero, is known as singular matrix.
Hence, $∣ ∣ 024 30 - 1 2 b 16 ∣ ∣ = 0$
Expanding along
$R_{1}$ , we get $0 (0 + 1) - 3 (12 - 4) + 2 b (- 2 - 0) = 0$
$\Rightarrow - 24 - 4 b = 0$
$∴$ $b = - 6$