Hydrochloric acid solutions A and B have concentration of 0.5 N and 0.1 N respectively. The volume of solutions A and B required to make 2 litres of 0.2 N hydrochloric are

Question

Hydrochloric acid solutions A and B have concentration of 0.5 N and 0.1 N respectively. The volume of solutions A and B required to make 2 litres of 0.2 N hydrochloric are (A) 0.5 L of A + 1.5 L of B (B) 1.5 L of A + 0.5 L of B (C) 1.0 L of A + 1.0 L of B (D) 0.75 L of A + 1.25 L of B

Tardigrade Admin · Accepted Answer

NV=N1V1+N2V2 0.2×2=0.5x+0.1(2-x) 0.4=0.5x+0.2-0.1x 0.2=0.4x x=(1/2)L=0.5L

Q. Hydrochloric acid solutions $A$ and $B$ have concentration of $0.5 N$ and $0.1 N$ respectively. The volume of solutions $A$ and $B$ required to make $2$ litres of $0.2 N$ hydrochloric are

$0.5 L o f A + 1.5 L o f B$

$1.5 L o f A + 0.5 L o f B$

$1.0 L o f A + 1.0 L o f B$

$0.75 L o f A + 1.25 L o f B$

$N V = N_{1} V_{1} + N_{2} V_{2}$
$0.2 \times 2 = 0.5 x + 0.1 (2 - x)$
$0.4 = 0.5 x + 0.2 - 0.1 x$
$0.2 = 0.4 x$
$x = \frac{1}{2} L = 0.5 L$

Q. Hydrochloric acid solutions A and B have concentration of 0.5N and 0.1N respectively. The volume of solutions A and B required to make 2 litres of 0.2N hydrochloric are

0.5LofA+1.5LofB

1.5LofA+0.5LofB

1.0LofA+1.0LofB

0.75LofA+1.25LofB