How many structural isomeric alkene possible for molecule formula C5H10 which can show geometrical isomerism?

Question

How many structural isomeric alkene possible for molecule formula C5H10 which can show geometrical isomerism? (A) 1 (B) 2 (C) 0 (D) 3

Tardigrade Admin · Accepted Answer

C5H10 textDOU = 5 + 1 - (1/2) × 10 =1 <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-l7v0xciafddh.png" /> For show geometrical isomerism

Q. How many structural isomeric alkene possible for molecule formula $C_{5} H_{10}$ which can show geometrical isomerism?

1

2

0

3

$C_{5} H_{10}$

$DOU = 5 + 1 - \frac{1}{2} \times 10$

$= 1$

For show geometrical isomerism

Q. How many structural isomeric alkene possible for molecule formula C5​H10​ which can show geometrical isomerism?

1

2

0

3

C5​H10​ DOU=5+1−21​×10 =1 For show geometrical isomerism

Q. How many structural isomeric alkene possible for molecule formula $C_{5} H_{10}$ which can show geometrical isomerism?

$C_{5} H_{10}$

$DOU = 5 + 1 - \frac{1}{2} \times 10$

$= 1$

For show geometrical isomerism