How many grams of a dibasic acid (mol. wt. =200 ) should be present in 100 ml of its aqueous solution to give decinormal strength?

Question

How many grams of a dibasic acid (mol. wt. =200 ) should be present in 100 ml of its aqueous solution to give decinormal strength? (A) 20 g (B) 2 g (C) 10 g (D) 1 g

Tardigrade Admin · Accepted Answer

For dibasic acid E=(M/2)=(200/2)=100 N=(W × 1000/E × V( text in ml )) (1/10)=(W × 1000/100 × 100)=W=1 g

Q. How many grams of a dibasic acid (mol. wt. $= 200$ ) should be present in $100 m l$ of its aqueous solution to give decinormal strength?

20 g

2 g

10 g

1 g

For dibasic acid $E = \frac{M}{2} = \frac{200}{2} = 100$

$N = \frac{W \times 1000}{E \times V ( in m l )}$

$\frac{1}{10} = \frac{W \times 1000}{100 \times 100} = W = 1 g$

Q. How many grams of a dibasic acid (mol. wt. =200 ) should be present in 100ml of its aqueous solution to give decinormal strength?

20 g

2 g

10 g

1 g

For dibasic acid E=2M​=2200​=100 N=E×V( in ml)W×1000​ 101​=100×100W×1000​=W=1g

Q. How many grams of a dibasic acid (mol. wt. $= 200$ ) should be present in $100 m l$ of its aqueous solution to give decinormal strength?

For dibasic acid $E = \frac{M}{2} = \frac{200}{2} = 100$

$N = \frac{W \times 1000}{E \times V ( in m l )}$

$\frac{1}{10} = \frac{W \times 1000}{100 \times 100} = W = 1 g$