How many elements are possible for 1 st period of periodic table if azimuthal quantum number can have integral values from 0, 1,2 ... (n + 1)?

Question

How many elements are possible for 1 st period of periodic table if azimuthal quantum number can have integral values from 0, 1,2 ... (n + 1)? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

n=1 l=0,1,2 S,P, d n=2 l= 0, 1, 2, 3 S,p, d,f 1S2 2P6 2S2 3d10 first period → 2+6=8

Q. How many elements are possible for 1 st period of periodic table if azimuthal quantum number can have integral values from $0, 1, 2... (n + 1)?$

$n = 1$
$l = 0, 1, 2$
$S, P, d$
$n = 2$
$l = 0, 1, 2, 3$
$S, p, d, f$
$1 S^{2} 2 P^{6} 2 S^{2} 3 d^{10}$
first period $\to 2 + 6 = 8$

Q. How many elements are possible for 1 st period of periodic table if azimuthal quantum number can have integral values from 0,1,2...(n+1)?

n=1 l=0,1,2 S,P,d n=2 l=0,1,2,3 S,p,d,f 1S22P62S23d10 first period →2+6=8

Q. How many elements are possible for 1 st period of periodic table if azimuthal quantum number can have integral values from $0, 1, 2... (n + 1)?$

$n = 1$
$l = 0, 1, 2$
$S, P, d$
$n = 2$
$l = 0, 1, 2, 3$
$S, p, d, f$
$1 S^{2} 2 P^{6} 2 S^{2} 3 d^{10}$
first period $\to 2 + 6 = 8$