How many coulombs are required to deposit 50 g of aluminium when the electrode reaction is Al3++3e- xrightarrowAl

Question

How many coulombs are required to deposit 50 g of aluminium when the electrode reaction is Al3++3e- xrightarrowAl  (A)  536111 C  (B)  536.111 C  (C)  96500 C  (D)  38600 C

Tardigrade Admin · Accepted Answer

Al3++3e- xrightarrowAl 1 mole of Al requires 3 moles of electrons or 3× 96500 C 1 mole of Al=27 g 27 g of Al require =3× 96500 C 50 g of Al require =(3× 96500× 50/27) =536111 C

Q. How many coulombs are required to deposit $50 g$ of aluminium when the electrode reaction is $A l^{3 +} + 3 e^{-} A l$

$536111 C$

$536.111 C$

$96500 C$

$38600 C$

$A l^{3 +} + 3 e^{-} A l$ 1 mole of $A l$ requires 3 moles of electrons or $3 \times 96500 C$ 1 mole of $A l = 27 g$ $27 g$ of $A l$ require $= 3 \times 96500 C$ $50 g$ of $A l$ require $= \frac{3 \times 96500 \times 50}{27}$ $= 536111 C$

Q. How many coulombs are required to deposit 50g of aluminium when the electrode reaction is Al3++3e−​Al

536111C

536.111C

96500C

38600C