How many carbon atoms are present in 0.35 mole of C6H12O6? (Given: textN textA = 6.023 × 1023 )

Question

How many carbon atoms are present in 0.35 mole of C6H12O6? (Given: textN textA = 6.023 × 1023 ) (A) 1.26 × 102 carbon atoms (B) 1.26 × 1024 carbon atoms (C) 1.26 × 1044 carbon atoms (D) 1.26 × 1048 carbon atoms

Tardigrade Admin · Accepted Answer

∵ 1moleofC6H12O6has= 6 0.35 mole of C6H12O6 has = 6 × 0.35 = 2.1 × 6.023 × 1023= 1.26 × 1024 carbon atoms

Q. How many carbon atoms are present in $0.35 m o l e$ of $C_{6} H_{12} O_{6} ?$
(Given: $N_{A} = 6.023 \times 1 0^{23}$ )

$1.26 \times 1 0^{2} c a r b o n a t o m s$

$1.26 \times 1 0^{24} c a r b o n a t o m s$

$1.26 \times 1 0^{44} c a r b o n a t o m s$

$1.26 \times 1 0^{48} c a r b o n a t o m s$

$∵ 1 m o l eo f C_{6} H_{12} O_{6} ha s = 6$
$0.35 m o l e o f C_{6} H_{12} O_{6} ha s = 6 \times 0.35$
$= 2.1 \times 6.023 \times 1 0^{23} = 1.26 \times 1 0^{24} c a r b o n a t o m s$

Q. How many carbon atoms are present in 0.35mole of C6​H12​O6​? (Given: NA​=6.023×1023 )

1.26×102carbonatoms

1.26×1024carbonatoms

1.26×1044carbonatoms

1.26×1048carbonatoms