How can a central iodine be bonded in octahedral para periodic acid?

Question

How can a central iodine be bonded in octahedral para periodic acid? (A) With two -O and five -OH groups (B) With one -O and four -OH groups (C) With two-O and three-OH groups (D) With one -O and five -OH groups

Tardigrade Admin · Accepted Answer

Molecular formula of para periodic acid is H5IO6 So, central iodine be bonded with one 'O' and five '-OH' groups

Q. How can a central iodine be bonded in octahedral para periodic acid?

With two -O and five -OH groups

With one -O and four -OH groups

With two-O and three-OH groups

With one -O and five -OH groups

Molecular formula of para periodic acid is $H_{5} I O_{6}$ So, central iodine be bonded with one 'O' and five '-OH' groups

Q. How can a central iodine be bonded in octahedral para periodic acid?

With two -O and five -OH groups

With one -O and four -OH groups

With two-O and three-OH groups

With one -O and five -OH groups

Molecular formula of para periodic acid is H5​IO6​ So, central iodine be bonded with one 'O' and five '-OH' groups

Molecular formula of para periodic acid is $H_{5} I O_{6}$ So, central iodine be bonded with one 'O' and five '-OH' groups